Distance between cities is 540 km. A bus left 1 city. After he drove 120 km, a car drove out to meet him with a speed of 20

Distance between cities is 540 km. A bus left 1 city. After he drove 120 km, a car drove out to meet him with a speed of 20 km / h more. They met 2 hours later. Find the speed of the bus and car.

Let the speed of the bus be X km / h, then the speed of the car is X + 20 km / h (since it is 20 km / h more than that of the bus).
While the car had just left the opposite city to meet the bus, the bus had already covered 120 km, heading towards the city from which the car had exited. Two hours later they met, that is, the car was driving for 2 hours. Let’s write down the general formula for the path:
S = V * t (where S is the path; V is the speed; t is the time).
This means that the car has traveled in total:
2 * (X + 20) = 2X + 40 (km).
540 – 120 = 420 (km).
420 – 2X + 40 (km) – the bus passed before the meeting with the car.
2X + 40 = 420 – 2X + 40;
2X + 40 – 420 + 2X – 40 = 0;
4X – 420 = 0;
4X = 420;
X = 420: 4;
X = 105.
Thus, the bus speed is 105 km / h. Then the vehicle speed:
105 + 20 = 125 (km / h) – vehicle speed.