# Divide the rectangle, the length of which is 27 cm, equally into 3 squares. Find the perimeter and area of this rectangle.

**Divide the rectangle, the length of which is 27 cm, equally into 3 squares. Find the perimeter and area of this rectangle. How much the area of two squares is less than the area of the entire rectangle.**

1) A rectangle is a quadrangle in which two opposite sides are equal and all four corners are the same. The perimeter of a rectangle is the sum of the lengths of all sides of the rectangle. The area of a rectangle is the space bounded by the sides of the rectangle, that is, within the perimeter of the rectangle: S = a * b.

2) By condition, the length of the rectangle is 27, it was divided into 3 lengths of the squares. We get: 27/3 = 9 cm. This is the width of the rectangle.

3) S = a * b = 27 * 9 = 243 cm ^ 2.

4) P = 2 (a + b) = 2 (27 + 9) = 36 * 2 = 72 cm.

5) The area of two squares is: S = 81 + 81 = 162, 243 – 162 = 81 cm ^ 2.