Draw a rectangle 4 cm wide and twice as long. Find the perimeter.

We are given a rectangle that is 4 centimeters wide, while its length is twice as large. We need to find the perimeter of this rectangle, now let’s get down to solving:

First, let’s find the length. By condition, it is 2 times larger than the width. Therefore, the length will be equal to: 4 * 2 = 8 centimeters;

Since in a rectangle the length and width are equal to each other, denoting the length with the letter a and the width with the letter b, the equality of finding the rectangle’s perimeter will be true: P = (a + b) * 2; Now let’s find the perimeter by substituting the values:

P = (4 + 8) * 2;

P = 24, hence the perimeter of the rectangle is 24 centimeters

Answer: The perimeter of the rectangle is 24 centimeters.