Draw up the reaction equations according to the chain of transformations: Ba – BaO – Ba (OH) 2 – Ba (NO3) 2

Ba – BaO – Ba (OH) 2 – Ba (NO3) 2
1) 2Ba + O2 = 2BaO (oxidation)
2) BaO + H2O = Ba (OH) 2 (add water and get barium hydroxide)
3) Ba (OH) 2 + 2HNO3 = Ba (NO3) 2 + 2H2O



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