Due to the interaction of sodium with saturated monohydric alcohol weighing 0.46 g, hydrogen is released in both 112 ml.

Due to the interaction of sodium with saturated monohydric alcohol weighing 0.46 g, hydrogen is released in both 112 ml. Determine the sum of the indices in the qosho alcohol formula

2CnH (2n + 1) OH + 2Na -> 2CnH (2n + 1) ONa + H2 As a result of the reaction, 0.122 / 22.4 = 0.005 mol of hydrogen is released.One mol of hydrogen requires 2 mol of alcohol per 0.005 mol of hydrogen 0.01 mol of alcohol 0.01 mol = 0.46 d 1 mol = 46 g 12n + 2n + 1 + 16 + 1 = 46 14n + 18 = 46 n = 2
The alcohol is ethyl C2H5OH.