During alcoholic fermentation of glucose, 0.23 kg of ethanol was obtained. What volume of carbon dioxide was formed during this?

The reaction equation for alcoholic fermentation can be written as follows:
С6Н12О6 = 2 С2Н5ОН + 2 СО2
The molar mass of ethanol is 46 g / mol; the molar volume of carbon dioxide is 22.4 l / mol (according to Avogadro’s law).
For a competent decision, we translate the units of mass: 0.23 kg. = 230 g.
Based on the equation, we will compose the proportion:
230 g of ethanol corresponds to X l. carbon dioxide as
2 * 46 g / mol of ethanol correspond to 2 * 22.4 l / mol of carbon dioxide.
X = (230 * 2 * 22.4) / (2 * 46) = 112 liters.
Answer: the volume of carbon dioxide is 112 liters.