During electrolysis, 2.45 g of zinc was released in 1 hour. Determine the current in the circuit.

The amount of substance released by one coulomb of electricity is called the electrochemical equivalent of A,
therefore G = A * Q; G = A * I * t,
where G is the amount of the isolated substance [gram]; Q is the amount of electricity;
I – electric current [Ampere]; t – time [Hour].
Each metal has its own electrochemical equivalent A.
A (zinc) = 1.22
Then:
I = G / (A * t) = 2.45 / (1.22 * 1) = 2 Amperes
Answer: 2 A