During emergency braking, a car moving at a speed of 20 m / s stopped after 5 s. Find the braking time.

V0 = 20 m / s.

V = 0 m / s.

t = 5 s.

S -?

With uniformly accelerated deceleration, the path S traversed by the body is determined by the formula: S = V0 * t – a * t ^ 2/2, where V0 is the body’s speed at the beginning of deceleration, t is the deceleration time, and is the acceleration during deceleration.

The acceleration of the car a when driving, we find according to the definition: a = (V – V0) / t.

Since the final speed is V = 0 m / s, the formula will take the form: a = – V0 / t.

The “-” sign indicates that the speed and acceleration are directed in opposite directions.

S = V0 * t – V0 * t ^ 2/2 * t = V0 * t – V0 * t / 2 = V0 * t / 2.

S = 20 m / s * 5 s / 2 = 50 m.

Answer: the braking distance was S = 50 m.



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