During emergency braking, the car stopped after t = 2s. Find the braking distance of the car

During emergency braking, the car stopped after t = 2s. Find the braking distance of the car s if it starts braking at a speed v0 = 10 m / s.

Initial data: t (time before stopping the car) = 2 s; V0 (vehicle speed before braking) = 10 m / s; V (final vehicle speed) = 0 m / s.

1) Determine the acceleration with which the vehicle speed decreased (slow motion): V = V0 + a * t; -V0 = a * t and a = -V0 / t = -10 / 2 = -5 m / s ^ 2.

2) Calculate the braking distance: S = (V ^ 2 – V0 ^ 2) / 2a = -V0 ^ 2 / 2a = -10 ^ 2 / (2 * (-5)) = -100 / (-10) = 10 m.

Check: S = | a * t ^ 2/2 | = 5 * 2 ^ 2/2 = 10 m.

Answer: The braking distance was 10 meters.