During the acceleration of a body weighing 2 kg, work of 32 J. to what speed the body was dispersed?

During the acceleration of a body weighing 2 kg, work of 32 J. to what speed the body was dispersed? what work has to be done to stop the body?

Data: m (mass of the accelerated body) = 2 kg; A (work done while accelerating the body) = 32 J; V0 (initial speed) = 0 m / s.

1) Determine the final acceleration speed: A = Ek1 – Ek0 = m * V ^ 2/2 – m * V0 ^ 2/2 = m * V ^ 2/2 – 0, whence V = √ (2A / m) = √ (2 * 3 ^ 2/2) = 5.66 m / s.

2) Calculate the work to stop the body: A = Ek1 – Ek2 = m * V ^ 2/2 – m * Vk ^ 2/2 = 2 * 5.662 / 2 – 2 * 0 ^ 2/2 = 32 J.

Answer: The body will reach a speed of 5.66 m / s; to stop it, you will need to do work of 32 J.