During the combustion of a mixture of methane and carbon dioxide with a volume of 40 liters, 60 liters

During the combustion of a mixture of methane and carbon dioxide with a volume of 40 liters, 60 liters of oxygen were consumed. Calculate the amount of carbon dioxide in the starting mixture, assuming that all measurements were made under the same conditions.

1. In this mixture, only methane can burn, since in carbon dioxide carbon is in the highest oxidation state and can no longer increase it. Let’s compose the methane combustion equation:

CH4 + 2O2 → CO2 + 2H2O;

2.Let’s find the volume of methane from the ratios of the stoichiometric coefficients of the equation:

V (CH4) = V (O2): 2 = 60: 2 = 30 L;

3.Calculate the volume of carbon dioxide in the initial mixture:

V (CO2) = V (mixture) – V (CH4) = 40 – 30 = 10 l;

4.Calculate the chemical amount of CO2:

n (CO2) = V (CO2): Vm = 10: 22.4 = 0.4464 mol.

Answer: 0.4464 mol.