During the crystallization of 300 grams of matter, 81 kJ of heat was released.

During the crystallization of 300 grams of matter, 81 kJ of heat was released. Determine the specific heat of crystallization of the substance.

These tasks: m (mass of the crystallized substance) = 300 g (in SI m = 0.3 kg); Q (heat released during crystallization) = 81 kJ (81 * 10 ^ 3 J).

The specific heat of crystallization of the taken substance is determined by the formula: λ = Q / m.

Let’s perform the calculation: λ = 81 * 10 ^ 3 / 0.3 = 270 * 10 ^ 3 J / kg (2.7 * 10 ^ 5 J / kg).

Answer: The specific heat of crystallization of the taken substance is 2.7 * 10 ^ 5 J / kg (the taken substance is iron).