During the crystallization of water, 1650 kJ of energy was released. How much ice did you get.

Initial data: Q (the amount of heat released during the crystallization of water) = 1650 kJ (1650 * 10 ^ 3 J).

Reference values: according to the condition λl (specific heat of crystallization of water) = 330 kJ / kg (330 * 10 ^ 3 J / kg).

We calculate the mass of the ice obtained by the formula: m = Q / λl.

Calculation: m = 1650 * 10 ^ 3 / (330 * 10 ^ 3) = 1650/330 = 5 kg.

Answer: When water crystallized, 5 kilograms of ice were obtained.



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