During the crystallization of water, an amount of heat of 102,000 J was given off. What is the mass of the ice obtained?
| September 5, 2021 | education
Crystallization of water: Q = L * m, where by condition Q = 102000 J; L (const) = 3.4 * 10 ^ 5 J / kg.
m = Q / L = 102000 / (3.4 * 10 ^ 5) = 0.3 kg = 300 g.
Answer: 5 kJ of heat was spent to heat the steel drill; the mass of the ice obtained is 300 g.
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