During the decomposition of 2H2O = 2H2 + O2, 54 g of water were consumed.

During the decomposition of 2H2O = 2H2 + O2, 54 g of water were consumed. Determine the volume of oxygen received.

Let us determine the amount of water substance n (w) = m (w) / M (w) = 54/18 = 3 mol, where m (w) is the mass of water, M (w) is the molar mass of water.

It can be seen from the reaction equation that the amount of the substance of the formed oxygen n (k) is two times less than the amount of the substance of the consumed water, that is, n (k) = n (s) / 2 = 3/2 = 1.5 mol.

Let us find the volume of released oxygen under normal conditions V (k) = n (k) * Vm, where Vm = 22.4 l / mol is the molar volume.

V (k) = 1.5 * 22.4 = 33.6 l