During the decomposition of 300 g of magnesium carbonate with a mass fraction of impurities

During the decomposition of 300 g of magnesium carbonate with a mass fraction of impurities of 45%, a gas was formed. Determine its volume.

The decomposition reaction of magnesium carbonate when heated is described by the following chemical equation:

MgCO3 = MgO + CO2 ↑;

Find the chemical amount of magnesium carbonate. To do this, we divide its weight by the mass of 1 mole of the substance.

M MgCO3 = 24 + 12 + 16 x 3 = 84 grams / mol;

N MgCO3 = 300 x 0.55 / 84 = 1.964 mol;

The same molar amount of carbon dioxide can theoretically be obtained.

In order to calculate its volume, you need to multiply the amount of the substance by the volume of 1 mole of gas (assuming a volume of 22.4 liters).

V CO2 = 1.964 x 22.4 = 43.9936 liters;