During the decomposition of 72 g of water under the action of an electric current, hydrogen was released

During the decomposition of 72 g of water under the action of an electric current, hydrogen was released, with which copper oxide (2) was reduced. Calculate the mass of copper obtained from the reaction.

The equation
CuO + H2 = Cu + H2O
n = m / M
M (H20) = 2 + 16 = 18
72/18 = 4
1 mol to 1 mol
4 mol to 4 mol
CuO = 4 mol
Mr (CuO) = 64 + 16 = 80
m (CuO) = 4 mol * 80 g / mol = 320 g.
Answer 320g copper turned out



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