During the electrolysis of a solution of copper sulfate (2), 32 g of copper were released at the cathode.

During the electrolysis of a solution of copper sulfate (2), 32 g of copper were released at the cathode. Draw up an electrolysis scheme, calculate the volume of gas generated in this case.

Cathodic process: Cu2 + + 2e = Cu0;

Anodic process: 2H2O – 4e = O2 + 4H +;

The overall equation is 2СuSO4 + 2H2O = 2H2SO4 + 2Cu + O2;

Let’s find the amount of copper substance:

n (Cu) = m (Cu) / M (Cu) = 32/64 = 0.5 mol;

According to the stoichiometry of the reaction:

n (O2) = 0.5n (Cu) = 0.25 mol;

Find the volume of oxygen:

V (O2) = n (O2) * VM = 0.25 * 22.4 = 5.6 liters.

Answer: V (O2) = 5.6 liters.