During the electrolysis of a solution of mercury chloride (2), 320 g of metal was formed.

During the electrolysis of a solution of mercury chloride (2), 320 g of metal was formed. Determinant of the volume of released gas.

HgCl2 = Hg + Cl2 (electrolysis)

Mercury is a released metal. Chlorine is an evolved gas.

Find the number of moles of mercury:

n (Hg) = m (Hg) / M (Hg)

n (Hg) = 320g / 201g / mol = 1.592 mol.

Let’s find the amount of chlorine mol:

n (Cl2) = n (Hg) = 1.592 mol.

Let’s find the volume of the released gas:

V (Cl2) = n (Cl2) * Vm

V (Cl2) = 1.592 mol * 22.4 l / mol = 35.66 l

Answer: the volume of gas released is 35.66 liters.