During the electrolysis of a solution of silver nitrate, silver with a mass of 9.4 g was released
| May 16, 2021 | education
During the electrolysis of a solution of silver nitrate, silver with a mass of 9.4 g was released. Determine the electric charge that passed through the solution.
Initial data: m (mass of silver released from the solution) = 9.4 g (9.4 * 10 ^ -3 kg).
Reference values: according to the condition k (electrochemical equivalent of silver) = 1.12 * 10 ^ -6 kg / C.
The charge that passed through the silver nitrate solution during electrolysis can be expressed from the formula: k = m / q, whence q = m / k.
Calculation: q = 9.4 * 10 ^ -3 / (1.12 * 10 ^ -6) ≈ 8393 Cl.
Answer: A charge of 8393 Cl passed through the solution of silver nitrate.
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