During the electrolysis of an aqueous solution of potassium nitrate, 25 liters of gas were released at the anode.

| May 10, 2021 | education

During the electrolysis of an aqueous solution of potassium nitrate, 25 liters of gas were released at the anode. The volume of gas evolved at the cathode is equal under normal conditions.

(1) During the electrolysis of potassium nitrate solution electrolysis, hydrogen was released at the cathode, and oxygen at the anode.

2H2O = 2H2 + O2.

Let us find the amount of the substance of the released gas at the anode (O2) by the formula:

n = V: Vn.

n = 25 L: 22.4 L / mol = 1.11 mol.

2.Let’s find the quantitative ratios of substances.

2H2O = 2H2 + O2.

According to the reaction equation, there is 2 mol of hydrogen for 1 mole of oxygen. Substances are in quantitative ratios 1: 2.

The amount of hydrogen will be 2 times more than the amount of oxygen.

n (H2) = 2n (O2) = 1.11 × 2 = 2.22 mol.

Let’s find the volume of hydrogen.

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 2.22 mol × 22.4 L / mol = 49.73 L = 50 L.

Answer: V = 50 liters.



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