During the electrolysis of sulfuric acid for t = 1.0 h, m = 0.3 g of hydrogen was released. Determine the power

| August 15, 2021 | education

During the electrolysis of sulfuric acid for t = 1.0 h, m = 0.3 g of hydrogen was released. Determine the power P spent on heating the electrolyte if its resistance R = 0.4 Ohm. (Electrochemical equivalent of hydrogen – k = 0.01 * 10 ^ -6 kg / C)

To find out the power spent on heating the taken sulfuric acid, we use the formula: P = I ^ 2 * R = (m / (Δt * k)) ^ 2 * R = m ^ 2 * R / (k ^ 2 * Δt ^ 2 ).

Const: k – electrochemical equivalent of hydrogen (according to the condition k = 0.01 * 10 ^ -6 kg / C).

Data: m – mass of released hydrogen (m = 0.3 g, in SI m = 0.3 * 10 ^ -3 kg); R is the resistance of sulfuric acid (R = 0.4 Ohm); Δt is the duration of electrolysis (Δt = 1 h = 3.6 * 10 ^ 3 s).

Let’s perform the calculation: P = m ^ 2 * R / (k ^ 2 * Δt ^ 2) = (0.3 * 10 ^ -3) ^ 2 * 0.4 / ((0.01 * 10 ^ -6) ^ 2 * (3.6 * 10 ^ 3) ^ 2) = 27.78 W.

Answer: To heat the taken sulfuric acid, a power of 27.78 watts was consumed.



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