During the fermentation of glucose, 23 g of ethanol was obtained, what volume of carbon dioxide was released during this.

1. Let’s compose the equation of glucose fermentation:

C6H12O6 → 2C2H5OH + 2CO2 ↑;

2. Let’s calculate the chemical amount of the ethanol obtained:

n (C2H5OH) = m (C2H5OH): M (C2H5OH);

M (C2H5OH) = 2 * 12 + 5 + 17 = 46 g / mol;

n (C2H5OH) = 23: 46 = 0.5 mol;

3. Determine the amount of carbon dioxide released:

n (CO2) = n (C2H5OH) = 0.5 mol;

4. Find the volume of gas:

V (CO2) = n (CO2) * Vm = 0.5 * 22.4 = 11.2 liters.

Answer: 11.2 liters.