During the interaction of 7.6 g of diatomic alcohol with sodium, 2.24 liters of gas were released.

| March 17, 2021 | education

During the interaction of 7.6 g of diatomic alcohol with sodium, 2.24 liters of gas were released. Establish the molecular formula of the gas.

Dihydric alcohol contains two hydroxo groups in each molecule: for example, ethylene glycol (HO-CH2-CH2-OH).

In the case of the interaction of dihydric alcohol with sodium, two types of glycolate are formed:

HO-CH2-CH2-OHa and NaO-CH2-CH2-OHa. Imagine that sodium atoms have replaced the hydrogen of the hydroxyl groups completely, i.e. we got only glycolate of the second type and write down the general formula of the chemical reaction:

HO-R-OH + 2Na -> NaO-R-OHa + H2;

Find the molecular weight of the dihydric alcohol:

x = 7.6 * 22.4: 2.24 = 76 (g).

This is propylene glycol: HO-CH2-CH2-CH2-OH.
As a result of the reaction, hydrogen gas H2 is formed.



One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.