During the interaction of iron (III) hydroxide with hydrochloric acid, a salt with a mass of 48.75 g was formed.

| September 23, 2021 | education

During the interaction of iron (III) hydroxide with hydrochloric acid, a salt with a mass of 48.75 g was formed. Find the mass of hydrochloric acid with a mass fraction of hydrogen chloride of 10% required for the reaction.

1. Let’s compose the equation of the reaction proceeding during the interaction of iron hydroxide with hydrochloric acid:

Fe (OH) 3 + 3HCl = FeCl3 + 3H2O;

2. Calculate the chemical amount of ferric chloride:

n (FeCl3) = m (FeCl3): M (FeCl3);

M (FeCl3) = 56 + 3 * 35.5 = 162.5 g / mol;

n (FeCl3) = 48.75: 162.5 = 0.3 mol;

3. Determine the amount of reacted hydrogen chloride:

n (HCl) = n (FeCl3) * 3 = 0.3 * 3 = 0.9 mol;

4. Let’s calculate the mass of hydrogen chloride:

m (HCl) = n (HCl) * M (HCl) = 0.9 * 36.5 = 32.85 g;

5. Find the mass of hydrochloric acid:

m (solution HCl) = m (HCl): w (HCl) = 32.85: 0.1 = 328.5 g.

Answer: 328.5 g.



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