During the interaction of zinc weighing 6.5 g with hydrochloric acid, hydrogen with a volume of 2 liters was released.

During the interaction of zinc weighing 6.5 g with hydrochloric acid, hydrogen with a volume of 2 liters was released. Determine the mass fraction of the hydrogen yield.

To obtain hydrogen, a method of dissolving zinc in hydrochloric acid is used.

Zn + 2HCl → ZnCl2 + H2;

The amounts of synthesized hydrogen and dissolved zinc are the same (equimolar).

N H2 = 2 / 22.4 = 0.089 mol;

To obtain this amount of hydrogen, 0.089 mol of zinc must be dissolved.

Let’s find its weight.

M Zn = 65 grams / mol;

m Zn = 65 x 0.089 = 5.785 grams;

The reaction yield is: 5.785 / 6.5 = 0.89 = 89%;