During the last second of free fall without initial velocity, the body flew 35 m.
September 12, 2021 | education
| During the last second of free fall without initial velocity, the body flew 35 m. Determine the height from which the body fell.
Data: S1 (distance that the body flew in the last second of free fall) = 35 m.
Reference values: g (acceleration of gravity, acceleration of a body) ≈ 10 m / s2.
1) The speed that the body developed until the last second of the fall (t1 = 1 s): S1 = V0 * t1 + 0.5g * t1 ^ 2, whence V0 = (S1 – 0.5g * t ^ 2) / t = ( 35 – 0.5 * 10 * 1 ^ 2) / 1 = 30 m / s.
2) The duration of the fall of the body: t = t0 + t1 = V0 / g + t1 = 30/10 + 1 = 4 s.
3) The height from which the body fell: S = 0.5 * g * t ^ 2 = 0.5 * 10 * 4 ^ 2 = 80 m.
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