During the oxidation of formic acid, a gas was obtained, which was passed through an excess

| January 3, 2021 | education

During the oxidation of formic acid, a gas was obtained, which was passed through an excess of calcium hydroxide solution. This resulted in the formation of a precipitate weighing 20 g. What mass of formic acid was taken for oxidation?

HOCON + [O] → CO2 + H2O.
Ca (OH) 2 + CO2 = CaCO3 ↓ + H2O.
Let’s find the amount of substance CaCO3.
n = m: M.
M (CaCO3) = 100 g / mol.
n = 20 g: 100 g / mol = 0.2 mol.
Let’s find the quantitative ratios of substances.
For 1 mol of CaCO3, there is 1 mol of CO2.
Substances are in quantitative ratios 1: 1.
The amount of CO2 and the amount of CaCO3 are equal.
n (CO2) = n (CaCO3) = 0.2 mol.
n (CO2) = n (HCOOH) = 0.2 mol.
Let’s find the mass of NSOOH.
M (HCOOH) = 46g / mol.
m = 46 g / mol × 0.2 mol = 9.2 g.
Answer: 9.2 g.



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