During the reaction of 13 g of divalent metal with water, 4.48 liters were released. hydrogen. Define metal.

1. Let’s compose the equation for the reaction of an unknown metal with water:

Me + 2H2O = Me (OH) 2 + H2 ↑;

2.Calculate the chemical amount of released hydrogen:

n (H2) = V (H2): Vm = 4.48: 22.4 = 0.2 mol;

3. Determine the amount of divalent metal entering into the reaction:

n (Me) = n (H2) = 0.2 mol;

4. calculate the molecular weight of the metal, and according to the table of D.I. Mendeleev, we find the unknown metal:

M (Me) = m (Me): n (Me) = 13: 0.2 = 65 g / mol.

Answer: Zn.