During the reaction of zinc with hydrochloric acid (Zn + 2HCl = ZnCl2 + H2), 44.8 liters of hydrogen were released

| April 30, 2021 | education

During the reaction of zinc with hydrochloric acid (Zn + 2HCl = ZnCl2 + H2), 44.8 liters of hydrogen were released. 1) What amount of acid substance must be taken for the reaction? 2) Calculate the mass of zinc involved in this reaction.

Let us find the amount of hydrogen substance: n = V / Vm, where Vm = 22.4 l / mol is the molar volume, a constant value for all gases at n. at. n (H2) = 44.8 L / 22.4 L / mol = 2 mol. According to the reaction from 2 mol of acid, 1 mol of hydrogen is obtained, which means n (HCl) / 2 = 2 / 1. n (HCl) = 2 * 2 = 4 mol. And from 1 mol of zinc, 1 mol of hydrogen is formed, which means n (H2) = n (Zn) = 2 mol. Zinc mass: m = n * M, where M = 65.4 g / mol (molar mass, determined from the periodic table). m (Zn) = 2 mol * 65.4 g / mol = 130.8 g.



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