During the roasting of zinc sulfide, 0.5 mol of zinc oxide was obtained. What volume of sulfur oxide 4 is formed?

Let’s compose the reaction equation, find the quantitative ratios of substances.

ZnS + O2 = ZnO + SO2 ↑.

According to the reaction equation, 1 mole of zinc oxide accounts for 1 mole of sulfur oxide. Substances are in quantitative ratios 1: 1.

The amount of substance will be equal.

n (ZnO) = n (SO2) = 0.5 mol.

Find the volume of sulfur oxide (IV).

V = Vn n, where Vn is the molar volume of gas, equal to 22.4 l / mol, and n is the amount of substance.

V = 0.5 mol × 22.4 L / mol = 11.2 L.

Answer: 11.2 liters.