During the same time, 5 C of the charge passed through one section of the circuit, and 15 C

During the same time, 5 C of the charge passed through one section of the circuit, and 15 C in the other. The current strength in which section of the circuit is greater and how many times?

The current strength in the circuit section can be calculated using the formula:

I = q / t, where q is the charge passed through the conductor (C), t is the time the charge passes through the conductor (s).

Current in the first section of the circuit:

I1 = q1 / t1, where q1 = 5 Cl.

Current in the second section of the circuit:

I2 = q2 / t2, where q2 = 15 Cl.

According to the condition of the problem, t1 = t2.

I2 / I1 = (q2 * t1) / (t2 * q1) = q2 / q1 = 15/5 = 3.

Answer: The current in the second section of the circuit is 3 times greater.