During the thermal decomposition of 25 g of calcium carbonate, carbon dioxide is released, determine:

During the thermal decomposition of 25 g of calcium carbonate, carbon dioxide is released, determine: a) the number of moles for the released gas b) mass c) volume d) the number of molecules.

The decomposition reaction of calcium carbonate when heated is described by the following chemical equation:

CaCO3 = CaO + CO2 ↑;

Let’s calculate the chemical amount of calcium carbonate. To do this, we divide its weight by the mass of 1 mole of the substance.

M CaCO3 = 40 + 12 + 16 x 3 = 100 grams / mol;

N CaCO3 = 25/100 = 0.25 mol;

The same molar amount of carbon dioxide would theoretically be synthesized.

To calculate its volume, you need to multiply the amount of substance by the volume of 1 mole of gas (filling volume 22.4 liters).

V CO2 = 0.25 x 22.4 = 5.6 liters;

The number of molecules will be:

K = 6.022 x 10 ^ 23 x 0.25 = 1.5055 x 10 ^ 23;