During the time t = 10 s, the body passed the path l = 60 m, while its speed increased 5 times.

| June 17, 2021 | education

During the time t = 10 s, the body passed the path l = 60 m, while its speed increased 5 times. Determine the acceleration of the body, considering it constant.

To calculate the constant velocity of the body in question, we use the formula: a = (V – V0) / t = (5V – V0) / t = 4V0 / t = 4 * (S / 3t) / t = 4S / 3t ^ 2; the initial velocity was expressed from the formula: S = (V + V0) * t / 2 = 6V0 * t / 2 = 3V0 * t, whence V0 = S / 3t.

Variables: S – distance traveled (S = 60 m); t – movement time (t = 10 s).

Calculation: a = 4S / 3t ^ 2 = 4 * 60 / (3 * 10 ^ 2) = 0.8 m / s2.

Check: S = V0 * t + a * t ^ 2/2 = S / 3t * t + a * t ^ 2/2 = S / 3 + a * t ^ 2/2 = 60/3 + 0.8 * 10 ^ 2/2 = 60 m (correct).

Answer: The constant acceleration of the body in question was 0.8 m / s2.



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