During the time t1 = 20 s, the body moved with a speed v1 = 20 m / s, the next time t2 = 20 s

During the time t1 = 20 s, the body moved with a speed v1 = 20 m / s, the next time t2 = 20 s – with a speed v2 = 30 m / s. what is the average body speed?

Given:

t1 = 20 seconds – time of movement in the first section;

v1 = 20 m / s – speed of movement in the first section;

t2 = 20 seconds – time of movement in the second section;

v2 = 30 m / s – speed of movement in the second section.

It is required to determine vav (m / s) – the average speed of body movement.

The length of the first section is:

S1 = v1 * t1 = 20 * 20 = 400 meters.

The length of the second section is:

S2 = v2 * t2 = 20 * 30 = 600 meters.

The total distance traveled is:

S = S1 + S2 = 400 + 600 = 1000 meters.

The total travel time is:

t = t1 + t2 = 20 + 20 = 40 seconds.

Then:

vav = S / t = 1000/40 = 25 m / s.

Answer: the average speed of a body is 25 meters per second.