Elevator motor power P = 1.2 kW. To what height does it evenly lift a load weighing m = 300kg for a period of time t = 30s.

univerkov | December 10, 2020 | education

P = A / t
A = Pt
1.2KW = 1200W
A = 1200W * 30sec = 36000 J
A = FS
F = gm = 10N / kg * 300kg = 3000N
S = A / F
S = 36000J / 3000N = 12m
Answer: the height is 12m.

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