Emergency braking of the vehicle lasted for 4 s. Determine what the braking distance was if the initial speed of the car is 90 km / h.
January 22, 2021 | education
| V0 = 25 m / s.
t = 4 s.
V = 0 m / s.
S -?
The path S covered by the body during uniformly accelerated braking is determined by the formula: S = V0 * t – a * t ^ 2/2, where V0 is the initial speed of movement, t is the braking time, and is the acceleration during braking.
Let us find the acceleration of the hoist a by the formula: a = (V0 – V) / t. Since V = 0 m / s, the formula will take the form: a = V0 / t.
The formula for determining the displacement will take the form: S = V0 * t – V0 * t ^ 2 / t * 2 = V0 * t – V0 * t / 2.
S = 25 m / s * 4 s – 25 m / s * 4 s / 2 = 50 m.
Answer: The braking distance during emergency braking is S = 50 m.
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