Energy of an electrostatic flat capacitor W = 10 mJ. If the charge of the capacitor is q = 50 μC, then its electrical capacity C is …
| February 9, 2021 | education
Initial data: W (energy of an electrostatic flat capacitor) = 10 mJ (10 * 10 ^ -3 J); q (charge of the taken flat capacitor) = 50 μC (50 * 10 ^ -6 C).
The electrical capacity of the taken electrostatic flat capacitor is determined by the formula: W = q2 / 2C, whence C = q2 / 2W.
Calculation: C = (50 * 10 ^ -6) 2 / (2 * 10 * 10 ^ -3) = 125 * 10 ^ -9 Ф (125 nF).
Answer: The electrical capacity of the electrostatic flat capacitor taken is 125 nF.
One of the components of a person's success in our time is receiving modern high-quality education, mastering the knowledge, skills and abilities necessary for life in society. A person today needs to study almost all his life, mastering everything new and new, acquiring the necessary professional qualities.
