Equate the straight line through the points M (-6; 9) K (-1; -1)

The straight line equation has the form y = kx + b. We substitute the coordinates of points M and K into this equation and find k and b, we have a system of equations:

-k + b = -1;

-6k + b = 9.

Multiply the first equation by (-1), get k – b = 1 and add it to the second equation

k – b + (-6k) + b = 9 + 1;

-5k = 10;

k = 10: (-5);

k = – 2.

Substitute the value k = -2 in the first equation of the system and find b, we get

2 + b = -1;

b = -1 – 2;

b = -3.

Hence, the equation of the line will have the form y = -2x – 3.