Equate the tangent to the graph y = x ^ 3 + 2x ^ 2-4x-3 and the point with the abscissa x = -2.

We find the equation of the tangent line, for this we find the value of the function and its derivative at the point of tangency.

Derivative of the function:

y ‘(x) = 3 * x² + 4 * x – 4.

Its value at the point of contact:

y ‘(- 2) = 3 * 4 – 4 * 2 – 4 = 12 – 8 – 4 = 0.

The value of the function at the touch point:

y (-2) = -8 + 8 + 8 – 3 = 5.

The general equation of the tangent line is f (x) = y ‘(x0) * (x – x0) + y (x0).

Therefore, in our case f (x) = 5.

Answer: the equation of the tangent line is f (x) = 5.