Equation of reaction of concentrated nitric acid and silver (1) with electronic balance.

Ag + HNO3 => AgNO3 + NO2 + H2O.
We arrange the oxidation states, taking into account the electronegativity of the atoms:
0 + 1 + 5-2 + 1 + 5-2 + 4-2 + 1-2
Ag + HNO3 => AgNO3 + NO2 + H2O.
Let’s write down the elements that have changed the number of atoms and arrange the coefficients:

0 +1
Ag – 1e = Ag. * 1 silver gives us electrons, it is a reducing agent.

+5 +4
N + 1 e = N. * 1 nitrogen accepts electrons it is an oxidizing agent.
Let us sum up the left and right sides of the sex reactions separately:
0 +5 +1 +4
Ag + N = Ag + N.
Now let’s put the coefficients into the equation:
Ag + 2HNO3 = AgNO3 + NO2 + H2O.