Equilateral triangle with a side equal to 10.3 meters. How many squares of 1 m2 fit in a triangle?

Let’s find the height by the Pythagorean theorem:
H = ((10.3) ^ 2 – (5.15) ^ 2) ^ (1/2) = (79.5675) ^ (1/2) ≈ 8.92 m.
No more than 8 squares with a side of 1 m.

Based on the base of the triangle, we calculate how many meters it is necessary to retreat from the corner of the triangle in order to place the whole squares.
Consider a right-angled triangle with a side of 1 m, which forms with a base 90º, and with a hypotenuse 30º.
By the sine theorem:
1 * tg30º = √3 / 3 ≈ 0.6.
This means that at the base of the triangle, it is necessary to subtract 0.6 m on each side, or only 0.6 * 2 = 1.2 m.

10.3 – 1.2 = 9.1 m.
The base will fit 9 squares with a side of 1 m.

We rise a meter higher in height and take away each time 1.2 m at the base.
9.1; 7.9; 6.7; 5.5; 4.3; 3.1; 1.9.
Therefore, 9 + 7 + 6 + 5 + 4 + 3 + 1 = 35 squares with sides of 1 m are placed in the triangle.