Establish the formula for saturated monohydric alcohol, the interaction of 0.46 grams

Establish the formula for saturated monohydric alcohol, the interaction of 0.46 grams of which with metallic sodium releases 112 milliliters of hydrogen.

Given:
CnH2n + 1OH
m (CnH2n + 1OH) = 0.46 g
V (H2) = 112 ml = 0.112 l

To find:
CnH2n + 1OH -?

Decision:
1) 2CnH2n + 1OH + 2Na => 2CnH2n + 1ONa + H2 ↑;
2) n (H2) = V (H2) / Vm = 0.112 / 22.4 = 0.005 mol;
3) n (CnH2n + 1OH) = n (H2) = 0.005 * 2 = 0.01 mol;
4) M (CnH2n + 1OH) = m (CnH2n + 1OH) / n (CnH2n + 1OH) = 0.46 / 0.01 = 46 g / mol;
5) M (CnH2n + 1OH) = Mr (CnH2n + 1OH) = Ar (C) * N (C) + Ar (H) * N (H) + Ar (O) * N (O);
46 = 12 * n + 1 * (2n + 2) + 16 * 1;
n = 2;
6) Unknown substance – C2H5OH.

Answer: Unknown substance – C2H5OH.