Ester weighing 10.56 g was obtained from acetic acid with a mass of 12 g and an excess of ethnicity.

Ester weighing 10.56 g was obtained from acetic acid with a mass of 12 g and an excess of ethnicity. What is the product yield?

Based on the process equation, we write the data:
m = 12 g m = 10.56 g; W -?

CH3COOH + C2H5OH = CH3COO – C2H5 + H2O – esterification, ethyl acetate is isolated;

We determine the molar masses of substances, as well as their amount:
M (CH3COOH) = 60 g / mol;

M (ethyl acetate) = 88 g / mol.

Y (CH3COOH) = m / M = 12/60 = 0.2 mol;

Y (sl. Ether) = 0.2 mol since the amount of these substances is 1 mol.

We find the mass of the product, its output:
m (word ether) = Y * M = 0.2 * 88 = 17.6 g (theoretical weight);

W = m (practical) / m (theoretical) * 100;

W = 10.56 / 17.6 * 100 = 60%

Answer: The ethyl acetate yield is 60%.