Ethanol weighing 84 g interacts with potassium. Calculate the amount of hydrogen released during this process.
| September 16, 2021 | education
The equation for the reaction of potassium with ethanol:
2K + 2C2H5OH = 2C2H5OK + H2
Amount of C2H5OH substance:
v (C2H5OH) = m (C2H5OH) / M (C2H5OH) = 84/46 (mol).
According to the reaction equation, 1 mol of H2 is formed from 2 mol of C2H5OH, therefore:
v (H2) = v (C2H5OH) / 2 = (84/46) / 2 = 42/46 (mol).
Thus, the volume of hydrogen evolved under normal conditions (n.a.):
V (H2) = v (H2) * Vm = (42/46) * 22.4 = 20.45 (l).
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