Ethylene glycol reacts with freshly precipitated copper hydroxide weighing 9.8 g.

Ethylene glycol reacts with freshly precipitated copper hydroxide weighing 9.8 g. Find the amount of ethylene glycol substance.

In accordance with the condition of the problem, we compose the reaction equation:
2C2H4 (OH) 2 + Cu (OH) 2 = 2H2O + C4H8O2Cu (OH) 2;
Let’s calculate the molar masses of substances:
M (ethylene glycol) = 62 g / mol;
M Cu (OH) 2 = 97.5 g / mol;
Determine the amount of mol of copper hydroxide if the mass is known:
Y Cu (OH) 2 = m / M = 9.8 / 97.5 = 0.1 mol;
Let’s calculate the number of moles of ethylene glycol:
X mol (ethylene glycol) – 0.1 mol Cu (OH) 2;
-2 mol -1 mol from here, X mol (ethylene glycol) = 2 * 0.1 / 1 = 0.2 mol;
Answer: for the reaction, ethylene glycol in the amount of 0.2 mol mol is required.