Every 10 seconds, 15 C of electricity passes along the spiral of the light bulb. What is the amperage in the lamp?
| February 16, 2021 | education
It is known that the current I is the amount of electricity q passing through the conductor cross-section per unit time t:
I = q / t.
Knowing the condition of the problem, we substitute the initial data into the indicated formula:
I = 15/10 = 1.5 (A).
Answer: the strength of the current flowing along the spiral of the lamp is 1.5 A.
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