External angles at the vertices AB of the triangle ABC = 125 ° and 115 °. Which side of the triangle is the largest

The outer corner KAB is adjacent to the inner corner BAC, triangle ABC. The sum of adjacent angles is 180, then the angle BAC = (180 – 125) = 55.

Similarly, the internal angle of the BCA = (180 – BCM) = (180 – 115) = 65.

Then the angle ABC = (180 – BAC – BCA) = (180 – 55 – 65) = 60.

The angle of the BCA is the largest angle of the triangle, therefore, the largest side AB lies opposite it

Answer: AB is the largest side of the triangle.