Find a mass of zinc that will react with a sulfuric acid solution if 112 liters of hydrogen are formed.

Find a mass of zinc that will react with a sulfuric acid solution if 112 liters of hydrogen are formed. How much sulfuric acid is needed for this?

1. Let’s write down the reaction equation:

Zn + H2SO4 = ZnSO4 + H2.

2. Find the amount of released hydrogen (Vm – molar volume, constant equal to 22.4 l / mol)

n (H2) = V (H2) / Vm = 112 L / 22.4 L / mol = 5 mol.

3. According to the reaction equation, we find the amounts of zinc and sulfuric acid, and then their mass:

n (Zn) = n (H2) = 5 mol.

m (Zn) = n (Zn) * M (Zn) = 5 mol * 65 g / mol = 325 g.

n (H2SO4) = n (H2) = 5 mol.

m (H2SO4) = n (H2SO4) * M (H2SO4) = 5 mol * 98 g / mol = 490 g.

Answer: m (Zn) = 325 g; m (H2SO4) = 490 g.