Find a three-digit number that can be divided without a remainder by 7, 8, or 9.

Consider the case where the number is divisible by 7:

a, x is the first digit, b, y is the second digit.

x = a, y = a * a + b.

If (ab – xy) is a multiple of 7.

You can also use a simpler method and multiply all the numbers, we get:

7 * 8 * 9 = 504.

Answer: 504.



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